2 minutes
Magnetic Field From Four Potential
The magnetic field for given potential
→B=∇×A Note several useful constants:
ℏc=197.326MeVfm e=√4π1137 β=√1−1/γ2
To determine the field at point given by →x x=→x0/ℏc y=→x1/ℏc z=→x2/ℏc
Then let: R=√x2+y2+(zγ)2
Now the Magnetic field is : →B=βγ(x,y,z)×→B0 →B=(yβγB0,−xβγB0,0)
where B0 is: B0=e24πZAuR3∫R/ℏc0r2ρ(r)drρ⋆ˆz ρ⋆=∫inf0r2ρ(r)dr
Compute B(r) with →x=(r,0,0) : |B(r)|=rβγe24πZAuR3∫R/ℏc0r2ρ(r)drρ⋆
Using a spherically symmetric Woods-Saxson distribution: ρ(r)=ρ0(1+w2r2/R2Au)1+e(r−RAu)/a with ρ0=3A4πR3Au
where: a is the skin depth, w is the ???, and RAu is the radius of the nucleus.
224 Words
2020-03-23 20:28 +0000
Read other posts